![SOLVED: The radius of a soap bubble is increased from 1/√(pi)cm to 2/√(pi)cm . If the surface tension of water is 30 dynes per cm , then the work done will be SOLVED: The radius of a soap bubble is increased from 1/√(pi)cm to 2/√(pi)cm . If the surface tension of water is 30 dynes per cm , then the work done will be](https://cdn.numerade.com/previews/aaa14013-4d5f-4b1b-84c7-ed819e870457_large.jpg)
SOLVED: The radius of a soap bubble is increased from 1/√(pi)cm to 2/√(pi)cm . If the surface tension of water is 30 dynes per cm , then the work done will be
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![The radius of a soap bubble is increased from 2√(pi) to 4√(pi) . If the surface tension of water is 70 dyne/cm then the work done will be The radius of a soap bubble is increased from 2√(pi) to 4√(pi) . If the surface tension of water is 70 dyne/cm then the work done will be](https://haygot.s3.amazonaws.com/questions/1965460_1104846_ans_58a4f9f4c13d40af886be3be9e9c9656.jpeg)
The radius of a soap bubble is increased from 2√(pi) to 4√(pi) . If the surface tension of water is 70 dyne/cm then the work done will be
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![A body of mass 20 g oscillates according to the equation x = 10 cos ( pi/5t + pi/6 ) cm . The maximum force acting on the body is in dyne: A body of mass 20 g oscillates according to the equation x = 10 cos ( pi/5t + pi/6 ) cm . The maximum force acting on the body is in dyne:](https://haygot.s3.amazonaws.com/questions/2050595_1150871_ans_ca43d93f086940f6b6b95005b858dc52.jpg)